Solve this:

92. The solubility of CaCO_​3 in water is 3.05 x 10^-4 moles/litre. Its solubility product will be :
(a) 6.1 x 10⁴
(b) 9.3
(c) 3.05 x 10^-4
(d) 9.3 x 10^-8

Dear Student,
 CaCO3 ↔ Ca++ + CO3^2-
• If S is the solubility of  CaCO₃ ,   therefore  Ksp = S $\times$ S
where  S is the solubility , S= ​3.05 X 10^-4 mole/ lit
Ksp= 3.05 X 10^-4 $\times$ 3.05 X 10^-4 = 9.3025X 10^-8 mol²/lit²


Regards