Solve this:
The solution is as follows:
CH3COOH + NaOH CH3COONa + H2O
Thus, concentration of HA = 0.1-0.02 = 0.8
concentration of A- = 0.1+0.8 = 0.18
So,
pH = pKa + log([HA]/[A-])
= 5.32
CH3COOH + NaOH CH3COONa + H2O
Thus, concentration of HA = 0.1-0.02 = 0.8
concentration of A- = 0.1+0.8 = 0.18
So,
pH = pKa + log([HA]/[A-])
= 5.32