Solve this:

97 .   A   l i t r e   o f   s o l u t i o n   c o n t a i n i n g   0 . 1   m o l e   o f   C H 3 C O O H   a n d   0 . 1   m o l e   o f   C H 3 C O O N a   p r o v i d e   a   b u f f e r   o f   p H   4 . 74 .   C a l c u l a t e   t h e   p H   o f   t h e   s o l u t i o n   a f t e r   t h e   a d d i t i o n   o f   0 . 02   m o l e   o f   N a O H .   K a   =   1 . 8   ×   10 - 5   ( a )   4 . 92   ( b )   4 . 03   ( c )   8 . 56   ( d )   5 . 32

The solution is as follows:

CH3COOH + NaOH  CH3COONa + H2O

Thus, concentration of HA = 0.1-0.02 = 0.8

  concentration of A- = 0.1+0.8 = 0.18 

So,

       pH = pK+ log([HA]/[A-])
              = 5.32

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