Solve this: A gaseous mixture was prepared by taking equal moles of N2 and O2 at room temperature If - Chemistry - Chemical Bonding and Molecular Structure

Question

Solve this:
A gaseous mixture was prepared by taking equal moles of
N2 and O2 at room temperature If total
pressure of the gaseous mixture was found to be 1 atm, then partial
pressure of nitrogen (N2) in the gaseous mixture is
:
(1) 0 6 atm (2) 1 atm
(3) 0 5 atm (4) 0 9 atm

Pradeep Sharma · Accepted Answer

dear student Ans is 0 5 , because the mole fraction is same due to
same NO of moles and the pressures in pure state is also same due
to same temperature and amount according to roults law partial
pressure =pressure of pure state × mol fraction I hope this
information will help you to clear your doubt

Solve this: A gaseous mixture was prepared by taking equal moles of N2 and O2 at room temperature. If total pressure of the gaseous mixture was found to be 1 atm, then partial pressure of nitrogen (N2) in the gaseous mixture is : (1) 0.6 atm (2) 1 atm (3) 0.5 atm (4) 0.9 atm

Solve this:
A gaseous mixture was prepared by taking equal moles of N₂ and O₂ at room temperature. If total pressure of the gaseous mixture was found to be 1 atm, then partial pressure of nitrogen (N₂) in the gaseous mixture is :
(1) 0.6 atm (2) 1 atm
(3) 0.5 atm (4) 0.9 atm