Solve this:
Find out the missing figures (denoted by stars) in the following equation the fractions being given in their lowest terms:
$$\begin{gathered} i) * \frac{3}{7} x 2 \frac{3}{*}=14\frac{*}{14} ii) 7\frac{*}{3}-*\frac{5}{11}=3\frac{*}{*3} \\ iii) 8\frac{9}{**}/*\frac{2}{27}=7\frac{16}{17} iv) 2\frac{1}{2}-3\frac{2}{3}+1\frac{5}{6}-\frac{2}{*}=0 \\ v) \frac{1}{2\frac{3}{4}}+ \frac{1}{5\frac{1}{5}}+\frac{1}{*}+\frac{1}{9\frac{8}{15}}=\frac{144}{143} \end{gathered}$$