Solve this:
Find the equivalent fraction of 9/4 that has :
a. Numerator = 16       b. Denominator = 81        c. Numerator = 24           d. Denominator = 45 

Dear Student,

Please find below the solution to the asked query:

We write  equivalent fractions of $\frac{9}{4}$ that has , As :

$$\begin{gathered} \mathrm{a}) \mathrm{Numerator} = 16 : \\ \frac{9}{4} = \frac{9\times {\displaystyle \frac{16}{9}}}{4\times {\displaystyle \frac{16}{9}}} = \frac{16}{{\displaystyle \frac{64}{9}}}= \frac{\mathbf{16}}{\mathbf{7}\mathbf{.}\mathbf{11}} \mathbf{(}\mathbf{ }\mathbf{Ans}\mathbf{ }\mathbf{\left)} \\ \mathrm{b}\right) \mathrm{Denominator} = 81 : \\ \frac{9}{4} = \frac{9\times {\displaystyle \frac{81}{4}}}{4\times {\displaystyle \frac{81}{4}}} = \frac{{\displaystyle \frac{729}{4}}}{{\displaystyle 81}}= \frac{\mathbf{182}\mathbf{.}\mathbf{25}}{\mathbf{81}} \mathbf{(}\mathbf{ }\mathbf{Ans}\mathbf{ }\mathbf{)} \\ \mathrm{c}) \mathrm{Numerator} = 24 : \\ \frac{9}{4} = \frac{9\times {\displaystyle \frac{24}{9}}}{4\times {\displaystyle \frac{24}{9}}} = \frac{{\displaystyle 24}}{{\displaystyle \frac{{\displaystyle 96}}{9}}}= \frac{\mathbf{24}}{\mathbf{10}\mathbf{.}\mathbf{67}} \mathbf{(}\mathbf{ }\mathbf{Ans}\mathbf{ }\mathbf{)} \\ \mathrm{d} ) \mathrm{Denominator} = 45 : \\ \frac{9}{4} = \frac{9\times {\displaystyle \frac{45}{4}}}{4\times {\displaystyle \frac{45}{4}}} = \frac{{\displaystyle \frac{405}{4}}}{{\displaystyle 45}}= \frac{\mathbf{101}\mathbf{.}\mathbf{25}}{\mathbf{45}} \mathbf{(}\mathbf{ }\mathbf{Ans}\mathbf{ }\mathbf{)} \end{gathered}$$

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