Solve this:
( i )   1 1 + a n - m + 1 1 + a m - n ( i i )   ( x a + b ) 2 × ( x b + c ) 2 × ( x c + a ) 2 ( x a .   x b .   x c ) 3

Dear student,

(i) We have,11+an-m+11+am-n=11+anam+11+aman                        ...[using  a-b=1ab]=amam+an+anan+am=am+anam+an=1(ii) xa+b2×xb+c2×xc+a2xa.xb.xc3= x2a+2b×x2b+2c×x2c+2ax3a.x3b.x3c      ...[using amn=am×n]=x2a+2b+2b+2c+2c+2ax3a+3b+3c            ...[using am×an=am+n]=x4a+4b+4cx3a+3b+3c                            =x4a+4b+4c-3a+3b+3c            ...[using aman=am-n]=x4a-3a+4b-3b+4c-3c=xa+b+c


Regards
 

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