Solve this:
In the circuit diagram given below, AB is a uniform wire of resistance 15 Ω and length I m. It is connected to a cell El of emf 2V and negligible internal resistance and a resistance R. The balance point with another cell E2 of emf 75 mV is found at 30 cm from end A Calculate the value of R. 



 


Dear Student,
                         current in loop AXE2GA=current in loop AE1BA ( In steady state)E230100×15=E1R+15or R+15=E1×4.5E2=2×4.575×10-3=120or R=105ohm
Regard

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