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Solve this :

In uniform circular motion particle moves with speed 5 m/s, then the change in magnitude of velocity of particle, when it moves from position A to B is
$a)5\sqrt{2}m/s\phantom{\rule{0ex}{0ex}}b)10m/s\phantom{\rule{0ex}{0ex}}c)Zero\phantom{\rule{0ex}{0ex}}d)2.5m/s$

Ans: c zero because there is no change in magnitude if any vector change it's position.