Solve this : Please solve my queries. Do not send any links. Q . Prove that sec 2 θ - sin 2 θ - 2 sin 4 θ 2 cos 4 θ - cos 2 θ = 1 Share with your friends Share 0 Varun Rawat answered this LHS = sec2θ - sin2θ - 2 sin4θ2 cos4θ - cos2θ= sec2θ - sin2θ1 - 2 sin2θcos2θ2 cos2θ - 1= sec2θ - sin2θcos2θ1 - 2 sin2θ21 - sin2θ - 1 as, sin2x + cos2x = 1= sec2θ - tan2θ1 - 2 sin2θ1 - 2 sin2θ= sec2θ - tan2θ=1=RHS 1 View Full Answer