Solve this plzzz.. Q3. A Zener diode is specified having a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. What is the maximum current that the diode can handle? Share with your friends Share 0 Aarushi Mishra answered this If power dissipated exceeds the maximum power dissipated then the diode will be damaged i.e. it will break down.Maximum power dissipation occurs at breakdown voltage.Power, P=360mW=0.36WV=9.1 voltsP=VII=PV=0.369.1=0.0396A=39.6mA 0 View Full Answer