Solve this problem. Please ignore the pen lines. Q.iii. In the figure, AB is the diameter of circle with centre of O. If ∠ A E D = 120 ° , find ∠ B C D . Share with your friends Share 0 Anuradha Sharma answered this Hi, We know that angle in semicrcle are 90 degree so angle ADB = 90 degreealso in cyclic quadrilateral ABDE, angle ABD+angle AED = 180 Property of ccyclic quadrilateral that opposite angle's sum is 180so angle ABD = 180 - 120 = 60 degreenow in triangle ADB, angle DAB +angle ABD+angle ADB = 180 so angle DAB = 180 - 90 -60 = 30 degreealso DABC is a cyclic quadrilaletral so angle DAB+angle BCD = 180 so angle BCD = 180-30 = 150 degree 6 View Full Answer