Solve this:

Q. 1. In the given figure,  A B C ~ A D E .   if AE=2 cm, EC=3cm and DE = 1.6 cm, then find BC. 



[Ans. BC=4 ( Using Thales' theorem)]







Q. 2. Mean of four observations is 12. If first, second, third and fourth observations are decreased by 1,2,3 and 4 respectively, then find the new means.  [Ans. New Mean =9.5]

Q. 3. A letter is chosen at random from the letter of the word "PROBABILITY". Find the probability that is is not a vowel.                          [Ans. 7/11]



 

Dear Student,

2. Mean = Sum of all observationsNumber of observations 12 = Sum of the four observations4  Sum of the four observations = 48When the first, second, third and fourth are decreased by 1, 2, 3 and 4 respectively, the total sum of the four observations decreases by 10.Thus, sum of the four observations = 48 - 10 = 38Therefore, new mean = 384 = 9.53. There are 11 letters in the word, "PROBABILITY", out of which 4 are vowels and 7 are consonants.A letter is either a vowel or a consonant.Therefore, probability that the letter chosen from the word "PROBABILITY" is not vowel = probability that the letter is a consonant = Number of favourable lettersTotal numbers of letters = 711

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