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Q.10. The following figure shows closed victory-stand whose dimensions are given in cm.


Find the volume and the surface area of the victory stand.

Total surface area of the cuboid = 2(L*B + B*H + H*L)

Figure 1 -

Length = 40 cm, Breadth = 30 cm and Height = 30 cm

TSA = 2(40*30 + 30*30 + 30*40)

= 2*(1200 + 900 + 1200)

= 2*3300

= 6600 sq cm

Figure 2 -

Length = 40 cm, Breadth = 30 cm and Height = 30 cm

TSA = 2(40*30 + 30*30 + 30*40)

= 2(1200 + 900 + 1200)

= 2*3300

= 6600 sq cm

Figure 3 -

TSA = 2(40*30 + 30*20 + 20*40)

= 2(1200 + 600 + 800)

= 2*2600

= 5200 sq cm

TSA of Victory Stand = 6600 + 6600 + 5200

= 18400 sq cm

Volume of Cuboid = L*B*H

Figure 1 -

Volume = 40*30*30

= 36000 cu cm

Figure 2 -

volume = 40*30*30

= 36000 cu cm

Figure 3 -

Volume = 40*30*20

= 24000 cu cm

Total volume of the Victory Stand = 36000 + 36000 + 24000

= 96000 cu cm

So, TSA of the Victory Stand is 18400 sq cm and Volume of the Victory Stand

Answer is 96000 cu cm
 
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