Solve this. Q.11. For the arrangement shown in figure, the magnetic induction at the centre C (1) 3 μ 0 I 16 R (2) μ 0 I 16 R (3) 5 μ 0 I 16 R (4) 16 μ 0 I 5 R Share with your friends Share 12 Vijay Shankar Yadav answered this Dear Student, In the figure there are two arcs larger one subtends 3π2 on the centre and smaller one π2So net magnetic field at the centre=μ0I2×2R×34-μ0I2R×14=μ0I16R Regards 1 View Full Answer