Solve this:
Q.15. A rod of mass m and length 2R can rotate about an axis passing through O in vertical plane. A disc of mass m and radius R is hinged to the other end P of the rod and can freely rotate about P. When disc is at lowest point both rod and disc has angular velocity  ω . If rod rotates by maximum angle θ = 60 ° with downward vertical, then find  ω in terms of R and g. (all hinges are smooth)

Dear Student ,
Here in this case the angular momentum of the rod is 112m2R2=13mR2 and the angular momentum of the disc is 12mR2.

Now as the rod and the disc rotates with same angular momentum ω when the disc is at lowest point and the rod rotates maximum with angle 600 then the angular momentum is , ω=34gR
Regards

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