Solve this:
Q.18. When an ideal gas is compressed adiabatically and reversibly, the final temperature is:
(a) higher than the initial temperature
(b) lower than the initial temperature
(c) the same as initial temperature
(d) dependent upon the rate of compression
Dear Student,
By applying 1st law,
dQ = dU + dW
for adiabatic dQ = 0
therefore, dU = -dW
Since dW is negative so work is done on the gas
it means dU is positive , so U is increasing.
U = Cp* T
So increase in U results in increase in temperature.
Hence, temperature increases.
Hence, option a is correct.
Regards,
By applying 1st law,
dQ = dU + dW
for adiabatic dQ = 0
therefore, dU = -dW
Since dW is negative so work is done on the gas
it means dU is positive , so U is increasing.
U = Cp* T
So increase in U results in increase in temperature.
Hence, temperature increases.
Hence, option a is correct.
Regards,