Solve this:
Q.24. A solenoid of length 20 cm and radius 2 cm is closely wound with 200 turns. The magnetic field intensity at either end of the solenoid when the current in the winding is 5 amp. is
1 ) 2500 Amp/m
2) 2000 Amp/m
3) 1750 Amp/m
4) 2940 Amp/m

Dear student

Magnetic field intensity is H=Bμo=μoni2μo=N×i2×L=200×50.2×2=5000.2=2500A/mRegards
Regards
 

  • 10
What are you looking for?