Solve this:
Q.3. If velocity of a particle is given by v = (2t + 3) m/s, then average velocity in interval 0 t 1 s is :
(1) 7 2 m/s
(2) 9 2 m/s
(3) 4 m/s
(4) 5 m/s

v=2t+3x=012t+3=t2+3t01=4 m average velocity =41= 4m/soption 3Regards

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v = 2t + 3


dx​ / dt = 2t + 3

dx = { 2t + 3 } dt

by integrating and taking limits [1-upper limit,0-lower limit]

x-xo=4

vavg=dx / dt

       = 4 / 1
        =4ms​1.
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