Solve this: Q.3. If velocity of a particle is given by v = (2t + 3) m/s, then average velocity in interval $0\le t\le 1s$ is : (1) $\frac{7}{2}$ m/s (2) $\frac{9}{2}$ m/s (3) 4 m/s (4) 5 m/s

• -2
v = 2t + 3

dx​ / dt = 2t + 3

dx = { 2t + 3 } dt

by integrating and taking limits [1-upper limit,0-lower limit]

x-xo=4

vavg=dx / dt

= 4 / 1
=4ms​1.
• -2
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