Solve this
Q.31. A reaction is second order in A and first order in B.
a) Write the differential rate equation.
b) How is rate affected on increasing the concentration of both A and B doubled?
c) How is the rate affected on increasing the concentration of A three times?
Given that Order of reactant A, x = 1 Order of reactant B, y = 2 The differential rate equation will be
Plug the value in this formula
Given that concentration of B is increased three times So that New concentration of B = 3[B] Plug the values we get new rate of reaction
Hence, the rate of reaction will increase by 9 times. (iii) Given that New concentrations of A = 2[A] New concentration of B = 2[B] Plug the values we get
