Solve this:
Q.43. In the circuit shown figure, the power which is dissipated as heat in the 6 Ω resistor is 6 W. What is the value of resistance R in the circuit?


1. 6 Ω
2. 10 Ω

let the current through 6 ohm is II26=6I=1 Aso 1 A current from battery.Req=R||8+6I=12R||8+612R||8+6=1R||8+6=12R||8=68RR+8=68R=6R+48R=24 ohm .Regards

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