Solve this:
Q.43. The least distance of vision of a longsighted person is 60 cm. By using a spectacle lens, this distance is reduced to 12 cm. The power of the lens is
(a) + 5.0 D
(b) + (20/3) D
(c) - (10/3) D
(d) + 2.0 D

Dear Student

v=-60 cmu =-12 cm1f=1v-1u=-160+112=-1+560=+460f =+15 cm =0.15mP=1f=10.15=10015=203D
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