Solve this: Q.46. In the reaction 2 P ( g ) + Q ( g ) ⇌ 3 R g + S g . If 2 mol each of P and Q taken initially in a 1 L flask. At equilibrium which is true:- (1) [P] < [Q] (2) [P] = [Q] (3) [Q] = [R] (4) None of these Share with your friends Share 6 Vartika Jain answered this Dear Student, 2P (g) + Q(g) ↔ 3R(g) + S(g)Initial 2 mol 2 mol 0 0At equil. 2-2x 2-x 3x xFrom the above table, we can see that[P] < [Q]Hence, correct answer is (1) 38 View Full Answer