Solve this:
Q.46. In the reaction 2 P ( g ) + Q ( g )   3 R g   + S g . If 2 mol each of P and Q taken initially in a 1 L flask. At equilibrium which is true:-
(1) [P] < [Q]
(2) [P] = [Q]
(3) [Q] = [R]
(4) None of these

Dear Student,

                      2P (g)    + Q(g)         3R(g)   +   S(g)Initial             2 mol           2 mol               0                 0At equil.        2-2x           2-x                3x               xFrom the above table, we can see that[P] < [Q]Hence, correct answer is (1)

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