# Solve this: Q.88. The heat generated in the circuit after closing the switch is (1) $\frac{C{V}^{2}}{2}$ (2) $C{V}^{2}$ (3) 2$C{V}^{2}$ (4) Zero

dear student
initial potential energy of the capacitor = 1/2 CV2
finally the negative plate of capacitor become positive charge
initial charge on capacitor plate= q=-CV
final charge=q=+CV total charge flown = 2q=2CV \
work done by battery= q(V) where q= total charge flown through battery
so  W= 2CV*V= 2CV2

as there is no change in the energy of capacitor so the total work done by battery is released in the form of heat energy

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