Solve this: Q.9. A Series LCR circuit is made by taking R = 100 Ω , L = 2 π H , C = 100 π μ F . This series combination is connected across an AC source of 220 V, 50 Hz. Calculate : (i) the impedance of the circuit. (ii) the peak value of the current flowing in the circuit. (iii) the power factor of this circuit and compare this with the one at its resonant frequency. [Ans. 100 2 Ω , 2 . 2 A , 1 2 , 1 2 ] Share with your friends Share 44 Shobhit Mittal answered this R=100 ohm , L=2π H,C=100π μFV=220v, f=50 Hz,Z=R2+ωL-1ωC2=10000+200-1002=1002 ohm .current I=2201002=2.22 A that the rms value.current peak value Imax=2I=2.2 A.tanϕ=ωL-1ωCR=100100=1ϕ=45 degree.power factor cosϕ=cos45=12power factor donot depend upon the frequency it will remain same .Regards 36 View Full Answer