Solve this:
Q. A body of mass 10 kg is moving with velocity 10 m/s. The work done to stop the body is
(A) + 500 J
(B) - 500 J
(C) + 1000 J
(D) - 1000 J

Dear Student ,
m= 10 kg v = 10 m /s KE= 12×10×10×10KE=500j 
The kinetic energy of a body of mass m=10kg moving at v=10m/s is E=(1/2)mv² After being stopped, the kinetic energy of the body has been transferred to work done (assuming no frictional loss), and has nothing left. So we can find Work done=loss/reduction in kinetic energy.
Regards

  • 0
m=10kg,v=10m/s, ke=1/2×10×10×10=500j The kinetic energy of a body of mass m=10kg moving at v=10m/s is E=(1/2)mv² After being stopped, the kinetic energy of the body has been transferred to work done (assuming no frictional loss), and has nothing left. So we can find Work done=loss/reduction in kinetic energy.
  • 2
What are you looking for?