Solve this : Q. A particle describes uniform circular motion in a circle of radius 2 m, with angular speed of 2 rad/. The magnitude of change in its velocity in π 2 s i s ○ Z e r o ○ 4 2 m / s ○ 8 m / s ○ 2 2 m / s Share with your friends Share 7 Shobhit Mittal answered this Dear Student, r=2m , ω=2 rad/s, angular displacement in π/2 sec=2*π2=π radian .velocity at t=0 u=2*2j^=4j^velocity at t=π/2 sec v=-2*2j^=-4j^change in velocity =-4j^-4j^=-8j^change in magnitude is 8 m/sRegards -7 View Full Answer