Solve this:

Q.  A person saves 180 minutes in covering a certain distance when he increases his speed form 25 km/h to 30 km/h.  Find the distance

(A) 250 km                           (B) 420 km 
(C) 450 km                           (D) 560 km

Dear Student

Let man travels distance S in t sec with speed 25km/h
Now when he travels same distance s with speed 30 km/h  then time taken by him is t -3 hr


So25 t =30 (t-3)25t=30t-905t=90t=18 hDistance = speed ×time=25 ×18=450 km
Regards

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S= ut +at^2 S=given A=9.8 m/s T=given U can find it now😊
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