Solve this:
Q. d x 4 + sin   2 x 2 =

Dear student
dx4+sin2x2=dx4+sin22xPut u=2xdx=du2=1214+sin2uduConsider,14+sin2uduUse sinu=tanusecuAlso, sec2u=1+tan2u=sec2u×15tan2u+4duPut v=tanudu=1sec2udv=15v2+4dvPut w=5v2dv=25dw=254w2+4dw=12511+w2dw=tan-1w25=tan-15v225=tan-15tanu 225Putting in solved integrals,1214+sin2udu=tan-15tanu 245=tan-15tan2x 245+C
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