Solve this:
Q. f   :   R R be defined by f x = x 1 + x 2 then (fofof) x = ?

Dear Student,
Please find below the solution to the asked query:

We have,fx=x1+x2fofx=ffx=fx1+x2=x1+x21+x1+x22=x1+x21+x21+x2=x1+x21+x2+x21+x2=x1+x21+2x21+x2=x1+2x2Now, fofofx=ffofx=fx1+2x2=x1+2x21+x1+2x22=x1+2x21+x21+2x2=x1+2x21+2x2+x21+2x2=x1+2x21+3x21+2x2So, fofofx=x1+3x2

Regards

  • 14
What are you looking for?