Solve this.

Q.  
If the end correction of an open organ pipe is 0.8 cm, then the inner radius of the pipe will be
 
1/2 cm

1/3 cm

2/3 cm

3/2 cm

Dear student,
End correction e = 0.6 RIn case of open pipe correction for both ends 2e=0.8e=0.4so 0.4=0.6RR=0.40.6=23cm

Option c is correct.

Regards

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