Solve this:
Q. If the standard electrode potential of /Cu electrode is 0.34 V, what is the electrode potential of 0.1 M concentration of ?
(1) 3.99 V
(2) 0.3105 V
(3) 0.222 V
(4) 0.176 V
Dear student ,
Ecell = Ecell0 - o.0592 /n log (product) / (reactant)
in the given question ; Cu++ + 2 e- = Cu
Ecell = 0.34 - 0.0592 / 2 log ( Cu) / Cu++
= 0.34 - 0.0592 / 2 log 1 / 0.1
= 0.3105 V (option 2)
Regards
Ecell = Ecell0 - o.0592 /n log (product) / (reactant)
in the given question ; Cu++ + 2 e- = Cu
Ecell = 0.34 - 0.0592 / 2 log ( Cu) / Cu++
= 0.34 - 0.0592 / 2 log 1 / 0.1
= 0.3105 V (option 2)
Regards