Solve this:
Q. If the standard electrode potential of C u 2 + /Cu electrode is 0.34 V, what is the electrode potential of 0.1 M concentration of C u 2 + ?
(1) 3.99 V
(2) 0.3105 V
(3) 0.222 V
(4) 0.176 V

Dear student ,
                        Ecell = Ecell0  - o.0592 /n  log (product) / (reactant)
in the given question ;  Cu++  +  2 e-  = Cu
                           Ecell‚Äč = 0.34  - 0.0592 / 2 log ( Cu) / Cu++
                                   =   0.34  - 0.0592 / 2 log 1 / 0.1
                                   =  0.3105 V  (option 2)
Regards

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