Solve this:
Q. In a common emitter transistor circuit, the base current is 40 μ A, then V B E is


(1) 2 V
(2) 0.2 V
(3) 0.8 V
(4) Zero

Dear student,

So correct option is (2)
Regards.

  • 10
just like kvl apply it towards one end

  • -33
Hope it helps.

  • 42
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