Solve this : Q In an isosceles triangle ABC, the coordinates - Maths - Straight Lines

Question

Solve this :

Q In an isosceles triangle ABC, the coordinates of the points B and
C on the base BC are respectively (1, 2) and (2, 1) If the equation
of the line AB is y   =   2 x , then the equation of the
AC is

a       y   =   1 2 x   - 1  
                 
                 
                 
        b         y  
=   x 2 ( c )       y   =   x - 1
                 
                 
                 
                 
        ( d )       2 y   =
  x + 3

Ankita Agarwal · Accepted Answer

Dear Student,

Two vertices are B1,2 and C2,1Let h,k be the coordinates of the vertex A of the ∆ABC
Since, AB=AC1-h2+2-k2=2-h2+1-k2h2+k2-2h-4k+5=h2+k2-4h-2h+5h=k    
1Again, Ah,k lies on the line AB whose equation isy=2x,then, k = 2h    
2From 1 and 2h=0,k=0Now, equation of the line joining the points A0,0 and C2,1 isy-0 =1-02-0x-0y=x2Hence option b is correct

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Solve this : Q. In an isosceles triangle ABC, the coordinates of the points B and C on the base BC are respectively (1, 2) and (2, 1). If the equation of the line AB is y = 2 x , then the equation of the AC is a y = 1 2 x - 1 b y = x 2 ( c ) y = x - 1 ( d ) 2 y = x + 3

Solve this :

Q. In an isosceles triangle ABC, the coordinates of the points B and C on the base BC are respectively (1, 2) and (2, 1). If the equation of the line AB is $y = 2 x,$ then the equation of the AC is

$(a) y = \frac{1}{2} (x - 1) (b) y = \frac{x}{2} (c) y = x - 1 (d) 2 y = x + 3$