Solve this:
Q). Obtain with the help of necessary diagram, the expression for the magnetic field in the interior of a toroid carrying current.

Dear Student,

(ii) A solenoid bent into the form of closed loop is called toroid. The magnetic field B has a constant magnitude everywhere inside the toroid.

(a) Let magnetic field inside the toroid be B along the considered loop 1 as shown in the figure.
Applying Ampere’s circuital law,


(b) Magnetic field inside the open space interior of the toroid Let the loop 2 be shown in the figure, experience magnetic field B.
No current threads the loop 2 which lie in the open space inside the toroid.
By Ampere’s circuital law,

Magnetic field in the open space exterior of the toroid Let us consider a coplanar loop 3 in the open space of exterior of toroid. Here, each turn of toroid threads the loop two times in opposite directions.
Therefore, net current threading the loop = NI-NI = 0
By Ampere’s circuital law,

Thus, there is no magnetic field in the open space interior and exterior of the toroid.

 

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