Solve this: Q The length of the latusrectum of a parabola is 4a A pair of perpendicular - Maths - Matrices

Question

Solve this:
Q The length of the latusrectum of a parabola is 4a A pair of
perpendicular tangents are drawn to the parabola to meet the axis
of the parabola at the points A, B If S is the focus of the
parabola then 1 S A + 1 S B =
A) 2/a
B) 4/a
C) 1/a
D) 2a

Shivam Mishra · Accepted Answer

Dear Student,
Please find below the solution to the asked query:

We know that tangent drawn at ends of latus ractum are perpendicular andmeet at directrix on axis of parabola
HenceFocus is a,0 and directrix meets axes at -a,0SA=a+a=2aSB=a+a=2a1SA+1SB=12a+12a=22a=1a Answer

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Solve this: Q. The length of the latusrectum of a parabola is 4a . A pair of perpendicular tangents are drawn to the parabola to meet the axis of the parabola at the points A, B. If S is the focus of the parabola then 1 S A + 1 S B = A) 2/a B) 4/a C) 1/a D) 2a

Solve this:
Q. The length of the latusrectum of a parabola is 4a . A pair of perpendicular tangents are drawn to the parabola to meet the axis of the parabola at the points A, B. If S is the focus of the parabola then $\frac{1}{|S A|} + \frac{1}{|S B|} =$
A) 2/a
B) 4/a
C) 1/a
D) 2a