Solve this:

Q.  The value for crystal field stabilisation energy is zero for 


( 1 )     K 2 ( M n F 6 ]                                               ( 2 )     K 3 [ F e ( C N ) 6 ]                                                   ( 3 )     K 3 [ F e F 6 ]                             ( 4 )     K 4 [ F e ( C N ) 6 ]

Dear student,
The splitting pattern in each complex compound is octahedral. If strong field ligand is present, then back pairing will take place as in case of (2) and (4) and splitting energy can never be zero since no electron will go into eg orbitals.. If strong field ligand is not present, back pairing will not happen as in case of (1) and (3).

Splitting pattern in K3FeF6 is

The splitting energy is equal to
C.F.S.E = -3 x 0.4Δ0  + 2 x 0.6Δ0 = 0.

Hence (3) is the correct option.

Hope it helps
Regards

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