Solve this.
Q. Two moles of oxygen gas undergoes a process given by P = $\frac{4}{1+{\left(\frac{V}{2}\right)}^2}$ where P is pressure (Pa) and V is volume ($m^3$). Find out the rms speed of gas molecule, when volume of gas becomes 4 $m^3$.
(1) 5$\sqrt{6}$ m/s
(2) 4$\sqrt{12}$ m/s
(3) 12 m/s
(4) 11.5 m/s