Solve this:

​Q1. A 2   +   2 B 2                                         A 2 B 4   and   3 2   A 2   +   2 B 2                                           A 3   B 4  
        Two substance A2 and B2 react in the above manner ; When A2 is limited it gives A2B4, When in excess gives A3B4, A2B4 can be converted to A3B4 when reacted with A2. Using this information, calculate the composition of the final mixture when mentioned amount of A2 and B2 are taken

(A) If 4 moles of A2 and 4 moles of B2 is taken in reaction container

(B) If  1 2  moles of A2 and 2 moles of B2 is taken in reaction container

(C) If  5 4  moles of A2 and 2 moles of B2 is taken

A2​+2B2​⟶A2​B4​ (limited A2​)
43​A2​+2B2​⟶A3​B4​ (limited A2​)
(A) 4A2​+4B2​⟶2A3​B4​+A2​
(B) 21​A2​+2B2​⟶21​A2​B4​+B2​
(C) 45​A2​+2B2​⟶21​A2​B4​+21​A3​B4​

  • -1
What are you looking for?