Solve this:

​Q27. If a + b + 2c = 0 , prove that a3 + b3 + 8c3 = 6abc.



​Q28. If a + b + c = 0, then find the value of  a 2 b c + b 2 c a + c 2 a b .


Q29. If x + y = 4, then find the value of x3 + y3 + 12 xy – 64.


Q30. Without actually calculating the cubes, find the values of :

         (i) (27)3 + (–17)3 + (–10)3                             (ii) (–28)3 + (15)3 + (13)3.
 

Hi, 27:We know that if x+y+z = 0 then x3+y3+z3= 3xyzhere x = a, y = b , z = 2c so putting these values hence , a3+b3+2c3= 3×a×b×2ca3+b3+8c3= 6abc Please post single query in a thread

  • 0
What are you looking for?