Solve this: Q45. Light of wavelength 6000 A falls on a single slit of width 0.1 mm. The second minimum will be formed for the angle of diffraction of (a) 0.08 radian (b) 0.06 radian (c) 0.12 radian (d) 0.012 radian Share with your friends Share 1 Shobhit Mittal answered this Dear Student, asinθ=nλfor small angle sinθ≈θθ=2*6000*10-1010-4=0.012 radian option dRegards 2 View Full Answer