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​Q49. X2 + Y2 ​ 2XY reaction was studied at a certain temperature. In the beginning 1 mole of X2 was taken in a one litre flask and 2 moles of Y2 was taken in another 2 litre flask. What is the equilibrium concentration of X2 and Y2 ? (Given equilibrium concentration of [XY] = 0.6 mol L–1).

      1   1 3 - 0 . 3   , 2 3 - 0 . 3 2   1 3 - 0 . 6   , 2 3 - 0 . 6 3   1   - 0 . 3 , 2   - 0 . 3 4   1   - 0 . 6 ,   2   -   0 . 6

Dear Student,

Final volume = 1+2=3 LInitial Cocentration of X2=1 mol3 LInitial Cocentration of Y2=2 mol3 L                   X2      +  Y2        2XYInitially       13            23                  0                 At equil.   13-x       23-x           2x    It is given that, 2x=0.6So, x=0.3Therefore, [X2]=13=0.3[Y2]=23-0.3Hence, correct answer is (1)

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