Solve this: Q49. X2 + Y2 ⇌ 2XY reaction was studied at a certain temperature. In the beginning 1 mole of X2 was taken in a one litre flask and 2 moles of Y2 was taken in another 2 litre flask. What is the equilibrium concentration of X2 and Y2 ? (Given equilibrium concentration of [XY] = 0.6 mol L–1). 1 1 3 - 0 . 3 , 2 3 - 0 . 3 2 1 3 - 0 . 6 , 2 3 - 0 . 6 3 1 - 0 . 3 , 2 - 0 . 3 4 1 - 0 . 6 , 2 - 0 . 6 Share with your friends Share 20 Vartika Jain answered this Dear Student, Final volume = 1+2=3 LInitial Cocentration of X2=1 mol3 LInitial Cocentration of Y2=2 mol3 L X2 + Y2 ↔ 2XYInitially 13 23 0 At equil. 13-x 23-x 2x It is given that, 2x=0.6So, x=0.3Therefore, [X2]=13=0.3[Y2]=23-0.3Hence, correct answer is (1) 60 View Full Answer