Solve this: Q59. What will be the heat of formation of KOH (s) if K S + H 2 O l → KOH aq + 1 2 H 2 g ; ∆ H = - 48 Kcal KOH s → KOH aq ; ∆ H = - 14 Kcal H 2 g + 1 2 O 2 g → H 2 O l ; ∆ H = - 68 Kcal (1) – 130 Kcal (2) – 102 Kcal (3) – 112 Kcal (4) – 170 Kcal Share with your friends Share 0 Megha Sharma answered this Dear student, So, ΔH = -48 * 2 + 14 - 68 -96 + 28 - 68 -76 kca refards 0 View Full Answer