Solve this: Q6. Simplify the following : (i) 8 2 n 3 × 64 - n 6 27 4 n 3 (ii) 2 n + 1 × 4 n + 1 2 n - 1 × 4 n - 1 (iii) 4 × 16 n + 1 - 16 × 4 2 n 4 × 4 2 n + 3 - 16 n + 1 (iv) 6 2 n + 3 36 n + 2 216 n + 1 2 3 Q7. Prove the following : (i) x b x a b + a - c x c x b c + b - a x a x c c + a - b = 1 (ii) x m x n 1 m n x n x r 1 n r x r x m 1 r m = 1 (iii) 1 1 - x m - n × 1 1 - x n - m = 1 (iv) x a - b a + b . x b - c b + c . x c - a c + a = 1 Q8. Find x, if (i) 3x + 1 = 1 27 x - 3 (ii) 25x – 1 = 23x + 1 (iii) 8x – 3 × 42x – 8 = (4) x–5 (iv) 2x = 1 2 . Share with your friends Share 0 Shruti Tyagi answered this Dear student, 7 iii) 11-xm-n+11-xn-m=1Taking L.H.S11-xm-n+11-xn-m=11-xmxn+11-xnxm=xnxn-xm+xmxm-xn=xnxn-xm-xmxn-xm=xn-xmxn-xm=1=R.H.SHence L.H.S=R.H.S 8 i) 3x+1=127x-3⇒3x+1=133x-3⇒3x+1=133x-9 --[using amn=am×n]⇒3x+1=3-3x-9 --[using a-m=1am]⇒3x+1=3-3x+9⇒3x×3=3-3x×39 --[using am×an=am+n]⇒3x3-3x=393⇒3x--3x=39-1 --[using a-m=1am]⇒3x+3x=38⇒34x=38Since the base is same so comparing the exponents⇒4x=8⇒x=84⇒x=2 Regards 2 View Full Answer Rishit Bhatevara answered this Which one to solve 0 Lakshmi Priya answered this Which one to answer 0