Solve this: Q7. Find the retarding potential required to stop electron of the de Broglie wavelength 0.5 nm. Hint : eV s = hc λ Share with your friends Share 9 Aarushi Mishra answered this De brogle wavelength, λ=hpWe knowp=2mK, where K is kinetic energyλ=h2mKBy energy conservationTotal initial enrgy=Total final energyTotal initial energy=K assuming potential to be zeroAs the electron moves through stopping potential region it will gain potential energy charge × potential difference=eVS and its velocity will become 0Total final energy =eVSK=eVSλ=h2meVSVS=hλ2meVS=h2λ2×2mePutting all valuesλ=0.5nm=5×10-10mm=9.11×10-31e=1.602×10-19h=6.626×10-34VS=6.02 VoltYou cannot use the formula given in hint eVS=hcλAs formula for energy, E=hcλ is valid only for photon and not for electron. Given formula is wrong 32 View Full Answer