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Question No. 13
A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. Power of the pulse is 30 mW and the speed of light is 3 × 10 8 m/s. The final momentum of the object is
A. 0.3 × 10 - 17   k g   m s - 1
B. 1.0 × 10 - 17   k g   m s - 1
C. 3.0 × 10 - 17   k g   m s - 1
D. 9.0 × 10 - 17   k g   m s - 1

Dear Student ,
Since the light pulse is completely absorbed by the object, the entire momentum of the pulse is transferred to the object. If E is the energy of the pulse, the momentum p is given by
 
            p =  E/c where c is the speed of light in free space.
 
But E = Pt where P is the power and t is the duration of the pulse.
 
Therefore, we have
 
             p = Pt/c = (30×10–3)×(100×10–9) /( 3×108) = 1×10–17 kg ms–1
 

Regards

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