Solve this:
Question No. 13
A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. Power of the pulse is 30 mW and the speed of light is 3 m/s. The final momentum of the object is
A. 0.3
B. 1.0
C. 3.0
D. 9.0
Dear Student ,
Regards
Since the light pulse is completely absorbed by the object, the entire momentum of the pulse is transferred to the object. If E is the energy of the pulse, the momentum p is given by
p = E/c where c is the speed of light in free space.
But E = Pt where P is the power and t is the duration of the pulse.
Therefore, we have
p = Pt/c = (30×10–3)×(100×10–9) /( 3×108) = 1×10–17 kg ms–1
Regards