Solve this: Question NO 6 ) If {( 1, 16), (0, 1), (1, 4) , (2, 25)} - Maths - Relations and Functions

Question

Solve this:

Question NO 6 ) If {( – 1, 16), (0, 1), (1,
4) , (2, 25)} ⊂ f, where f : R →
R, is a quadratic function, then the function f(x)
is

(A) 9x2 + 6x +1

(B) 9x2 – 6x + 1

(C) 3x2 + 2x + 1

(D) 3x2 – 2x + 1

Aarushi Mishra · Accepted Answer

-1, 16, 0,1, 1,4, 2,25⊂ff:ℝ→ℝ f contains elements -1, 16, 0,1, 1,4 and 2,25f-1=16f0=1f1=4 and so on
Since fx is quadraticLet fx=ax2+bx+cf0=10+0+c=1c=1fx=ax2+bx+1f1=4a+b+1=4a+b=3 ________1f-1=16a-b+1=16a-b=15 ___________2Adding equation 1 and 22a=18a=9a-b=159-b=15b=-6fx=9x2-6x+1

Solve this: Question NO.6 ) If {( – 1, 16), (0, 1), (1, 4) , (2, 25)} ⊂ f, where f : R → R, is a quadratic function, then the function f(x) is (A) 9x2 + 6x +1 (B) 9x2 – 6x + 1 (C) 3x2 + 2x + 1 (D) 3x2 – 2x + 1

Solve this:

Question NO.6 ) If {( – 1, 16), (0, 1), (1, 4) , (2, 25)} $\subset$ f, where f : R $\to$ R, is a quadratic function, then the function f(x) is

(A) 9x² + 6x +1

(B) 9x² – 6x + 1

(C) 3x² + 2x + 1

(D) 3x² – 2x + 1