solve this question please

solve this question please Calculate the mean deviation from median for the following: Marks 0-20 Nov of students 10 20-40 40„60 6000 16 30 32 80,100 12

Dear Student

Marks	Frequency	Mid Value	cf	|dm| = |X-Median|	f|dm|
0-20	10	10	10	20	200
20-40	16	30	26	14	224
40-60	30	50	56	0	0
60-80	32	70	88	2	64
80-100	12	90	100	18	216
	100			54	704

Median =  Size of (N/2) th term
Median = Size of (100/2)th term
Median = 50th term
             
50th item lies in the 56th cumulative frequency of the series. So 40-60 will be the median class interval.
Hence median value of the series is - 
$$\begin{gathered} M = l_1 + \frac{{\displaystyle \frac{N}{2}}+c.f.}{f}X i \\ M = 40 + \frac{{\displaystyle 50+26}}{30}X 20 \\ M = 40 + 50.67 \\ M = 90.67 \end{gathered}$$

Thus , mean deviation from Median 
$$\begin{gathered} M{D}_{m }= \frac{\sum _{\left|fdm\right|}}{\sum _f} \\ M{D}_{m }= \frac{704}{100} \\ M{D}_{m }= 7.04 \end{gathered}$$


Regards