Solve this question. Write answer in detail. Thank you.

Dear Student,

gof(x) = g(f(x)) 
Domain of g(f(x)) is range of f(x) and range of f(x) is always greater than or equal to 0 as the value of square root is either 0 or any positive real number.
Therefore, domain of gof(x) = [0, $\infty$)
g(f(x)) = ${\left(f\left(x\right)\right)}^2 - 1 = {\left(\sqrt{x}\right)}^2 - 1 = x - 1$
as minimum value of x possible is 0, therefore minimum value of g(f(x)) = 0-1 = -1 and maximum is infinity