Solve this question Share with your friends Share 0 Atul Shaw answered this Dear student,∫cos x-cos 2x1- cos xdx=∫cos x-(2cos2 x-1)1-cos x dx=∫cos x-2cos2 x+11-cos x dx=∫2cos2 x-cos x-1cos x-1 dx=∫2cos2 x-2cos x+cos x-1cos x-1 dx=∫2cos x(cos x-1)+1(cos x-1)cos x-1 dx=∫(2 cos x+1)(cos x-1)(cos x-1) dx=∫(2cos x+1) dx=∫2 cos x dx+∫1 dx=2 sin x+x+Ca. cos 2x=2 cos2 x-1Regards 0 View Full Answer