Refering to the given figure-
Height of tower = AB = 100m
CD =
x m
tan 45
o = AB/BC
Also,
tan 45
o = 1
Therefore-
AB/BC = 1
AB = BC = 100m ........(1)
tan 30
o = AB/BD = AB/(BC + CD)
Also,
tan 30
o = 1/(3)
1/2
Therefore,
AB/(BC + CD) = 1/(3)
1/2
AB = (BC + CD)/(3)
1/2 .........(2)
From 1&2-
100 = (BC + CD)/(3)
1/2
100 = (100 +
x)/(3)
1/2
100(3)
1/2 - 100 = x
100 [(3)
1/2 - 1] m = x
